## comparing the probability fallacy and the percentage fallacy.

What is the probability that you obtain 1 six given 4 trials of rolling a six-sided dice.

$\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}?$

correct answer: $1-(1-\frac{1}{6})^4.$

What is the overall percentage discount of getting first an r% discounted followed by another s% discount?

r+s %?